Q 1 :

A straight line L through the point (3, -2) is inclined at an angle 60° to the line 3x+y=1. If L also intersects the x-axis, then the equation of L is        [2011]

  • y+3x+2-33=0

     

  • y-3x+2+33=0

     

  • 3y-x+3+23=0

     

  • 3y+x-3+23=0

     

(2)

Let the slope of line L be m. Then

|m+31-3m|=3

[IMAGE 293]

m+3=±(3-3m)

4m=0 or 2m=23m=0 or m=3

 L intersects x-axis,   m=3

 Equation of L is y+2=3(x-3)

3x-y-(2+33)=0



Q 2 :

Let PS be the median of the triangle with vertices P(2,2), Q(6,-1) and R(7, 3). The equation of the line passing through (1,-1) and parallel to PS is        [2000]

  • 2x-9y-7=0

     

  • 2x-9y-11=0

     

  • 2x+9y-11=0

     

  • 2x+9y+7=0

     

(4)

S is the midpoint of Q and R

 S(7+62,3-12)=(132,1)

[IMAGE 294]

Now slope of PS=2-12-132=-29

Now equation of the line passing through (1,-1) and parallel to PS is

y+1=-29(x-1)2x+9y+7=0