Let O(0, 0), P(3, 4), Q(6, 0) be the vertices of the triangle OPQ. The point R inside the triangle OPQ is such that the triangles OPR, PQR, OQR are of equal area. The coordinates of R are [2007]
(3)
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Area of the triangle formed by the line and angle bisectors of the pair of straight lines is [2004]
2 sq. units
4 sq. units
6 sq. units
8 sq. units
(1)
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Orthocentre of triangle with vertices (0, 0), (3, 4) and (4, 0) is [2003]
(3)
We know that point of intersection of altitudes of a triangle is the orthocentre of the triangle.
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The number of integral points (integral point means both the coordinates should be integer) exactly in the interior of the triangle with vertices (0, 0), (0, 21) and (21, 0) is [2003]
133
190
233
105
(2)
Total number of points within the square
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A straight line through the origin O meets the parallel lines and at points and respectively. Then the point O divides the segment PQ in the ratio [2002]
1 : 2
3 : 4
2 : 1
4 : 3
(2)
The given lines are
Signs of constants on R.H.S. show that two lines lie on opposite sides of origin. Let a line through origin meets these lines in and respectively. Then required ratio is
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Area of the parallelogram formed by the lines and equals [2001]
(4)
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The number of integer values of , for which the -coordinate of the point of intersection of the lines and is also an integer, is [2001]
2
0
4
1
(1)
On equating the value of from both equations to get the -coordinate of the point of intersection,
For to be an integer, should be a divisor of 5 i.e., or
(not an integer)
(integer)
(not an integer)
(integer)
The incentre of the triangle with vertices and is [2000]
(4)
Let and are the coordinates of vertices A, O, B of .
AO = OB = AB. So, it is an equilateral triangle and the incentre coincides with centroid.
Incentre