Let P S be the median of the triangle with vertices P ( 2 , 2 ) , Q ( 6 , - 1 ) and R ( 7 , 3 ) . The equation of the line passing through ( 1 , - 1 ) and parallel to P S is [2000]

Question

Let $P S$ be the median of the triangle with vertices $P (2, 2), Q (6, - 1)$ and $R (7, 3)$ . The equation of the line passing through $(1, - 1)$ and parallel to $P S$ is [2000]

Smart Achievers · Accepted Answer

(4)

$S$ is the midpoint of $Q$ and $R$

$∴$ $S \equiv (\frac{7 + 6}{2}, \frac{3 - 1}{2}) = (\frac{13}{2}, 1)$

$Now slope of P S = \frac{2 - 1}{2 - \frac{13}{2}} = - \frac{2}{9}$

Now equation of the line passing through $(1, - 1)$ and parallel to $P S$ is

$y + 1 = - \frac{2}{9} (x - 1) \Rightarrow 2 x + 9 y + 7 = 0$

Solution

Q.
Let $P S$ be the median of the triangle with vertices $P (2, 2), Q (6, - 1)$ and $R (7, 3)$ . The equation of the line passing through $(1, - 1)$ and parallel to $P S$ is [2000]

1 $2 x - 9 y - 7 = 0$

2 $2 x - 9 y - 11 = 0$

3 $2 x + 9 y - 11 = 0$

4 $2 x + 9 y + 7 = 0$

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Solution

Q. Let PS be the median of the triangle with vertices P(2,2), Q(6,-1) and R(7, 3). The equation of the line passing through (1,-1) and parallel to PS is [2000]

1 2x-9y-7=0

2 2x-9y-11=0

3 2x+9y-11=0

4 2x+9y+7=0