Q 1 :

Consider two Group IV metal ions X2+ and Y2+.

A solution containing 0.01 M X2+ and 0.01 M Y2+ is saturated with H2S. The pH at which the metal sulphide YS will form as a precipitate is ________. (Nearest integer)

(Given: Ksp(XS)=1×10-22 at 25°C, Ksp(YS)=4×10-16 at 25°C,

[H2S]=0.1 M in solution,  Ka1×Ka2(H2S)=1.0×10-21, log2=0.30,  log3=0.48,  log5=0.70)                 [2026]

 



(4)

XS(s)X2+(aq)+S2-(aq)

For precipitation of XS(s)

[X2+][S2-]Ksp(XS)

[S2-]1×10-220.01=10-20

YS(s)Y2+(aq)+S2-(aq)

For precipitation of YS(s)

[Y2+][S2-]Ksp(YS)

[S2-]4×10-1610-2=4×10-14

Now, H2S(aq)2H+(aq)+S2-(aq)

[S2-][H+]2[H2S]=Ka1×Ka2=1×10-21

[S2-]=1×10-21×[H2S][H+]24×10-14

[H+]214×10-7×10-1

[H+]12×10-4pH4.3



Q 2 :

The first and second ionization constants of H2X are 2.5×10-8 and 1.0×10-13 respectively. The concentration of X2- in 0.1 M H2X solution is______×10-15 M. (Nearest Integer)         [2026]



(100)

H2XH++HX-0.1-xx+yx-y

2.5×10-8=(x+y)(x-y)0.1-x

HX-H++X2-x-yx+yy

1×10-13=(x+y)(y)x-y

Approximate : Ka1Ka2So xy

x+yx,    x-yx

10-13=x·yx

y=10-13

[X2-]=10-13

[X2-]=100×10-15



Q 3 :

Consider the following statements:

A) BF3 does not have a proton but still acts as an acid

B) Strong acids have very strong conjugate bases

C) Stronger acid donates a proton to the stronger base

Incorrect statement(s) is/are:

  • (A) only

     

  • (B) only

     

  • (A) and (B) only

     

  • (A) and (C) only

     

(2)

 



Q 4 :

100 mL of 0.5 M Na3PO4 aqueous solution is mixed with 80 mL of 1.25 M HCl solution. The pH of the final solution is (Given: Ka1,Ka2,Ka3 of H3PO4 are 10-3,10-5 and 10-7 respectively)

  • 6

     

  • 4

     

  • 3.5

     

  • 4.7

     

(2)

Hint: m. moles of Na3PO4=50

M moles of HCl = 100

Final solution will have NaH2PO4 (amphoteric salt)

       pH=pKa1+pKa22=4