Q 11 :

A parallel plate capacitor of capacitance 2F is charged to a potential V. The energy stored in the capacitor is E1. The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is E2. The ratio E2/E1 is            [2023]

  • 2 : 1

     

  • 1 : 2

     

  • 1 : 4

     

  • 2 : 3

     

(2)

Initially,

Q1=CV=(2)V

E1=12CV2=12(2)V2=V2

Finally,

Charge on each capacitor,

       Q2=Q12=2V2=V

        E2=2(12Q22C)=V22

    E2E1=12



Q 12 :

A capacitor of capacitance  900μFis charged by a 100 V battery. The capacitor is disconnected from the battery and connected to another uncharged identical capacitor such that one plate of the uncharged capacitor is connected to the positive plate and the other plate of the uncharged capacitor is connected to the negative plate of the charged capacitor. The loss of energy in this process is measured as x×10-2J. The value of x is ________ .           [2023]



(225)

C=900μF

Hence Q=CV=900×10-6×100=9×10-2=90 mC

Common potential will be developed across both capacitors by KVL.

Total charge on left plates of capacitors should be conserved.

  90 mC+0=2CV0

CV0=45 mC

Heat dissipated=Ui-Uf    [Change in energy stored in the capacitors]

=12(90 mC)2900μF-2×12(45 mC)2900μF [U=Q22C]

=12×900×10-6(8100-4050)×10-6=2.25 Joule



Q 13 :

A 600 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. Electrostatic energy lost in the process is __________μJ           [2023]



(6)

Q=CV=600×10-12×200=12×10-8 C

Initial energy=12CV2

                          =12×600×10-12×(200)2=12μJ

When connected to another uncharged capacitor

charge will be equally distributed on identical capacitors

          Q'=Q2=6×10-8

Final energy=2×Q'22C=Q'2C

       =(6×10-8)2600×10-12=6μJ

Energy lost=Initial energy-Final energy

                       =(12-6)μJ=6μJ



Q 14 :

In the given circuit, C1=2μF, C2=0.2μF, C3=2μF, C4=4μF, C5=2μF, C6=2μF, the charge stored on capacitor C4 is ______ μC.                  [2023]



(4)

Ceq=0.5μF

Q=0.5×10=5μC

Q'=5μC×0.80.8+0.2=4μC



Q 15 :

In the given figure, the total charge stored in the combination of capacitors is 100μC. The value of 'x' is _________ .       [2023]



(5)

Charge on C1 is Q1=2×10=20μC                    ...(i)

Charge on C2 is Q2=x×10=10xμC                  ...(ii)

Charge on C3 is Q3=3×10=30μC                     ...(iii)

Total charge =20+10x+30=100

  x=5



Q 16 :

The space between the plates of a parallel plate capacitor of capacitance C (without any dielectric) is now filled with three dielectric slabs of dielectric constants K1=2, K2=3, and K3=5 (as shown in the figure). If the new capacitance is n3C, then the value of n is _______.                [2026]



(8)

 



Q 17 :

Three parallel plate capacitors each with area A and separation d are filled with two dielectrics (k1 and k2) in the following fashion. Which of the following is true? (k1>k2)     [2026]

  • CA>CC>CB

     

  • CC>CA>CB

     

  • CB>CC>CA

     

  • CC>CB>CA

     

(1)

 



Q 18 :

A capacitor P with capacitance 10×10-6F is fully charged with a potential difference of 6.0 V and disconnected from the battery. The charged capacitor P is connected across another capacitor Q with capacitance 20×10-6F. The charge on capacitor Q when equilibrium is established will be α×10-5C

(assume capacitor Q does not have any charge initially), the value of α is __________.   [2026]



4