Q 1 :

A capacitor of capacitance C and potential V has energy E. It is connected to another capacitor of capacitance 2 C and potential 2 V. Then the loss of energy is x3E, where x is ______ .               [2024]



(2)     Initial potential energy of system

          ⇒12CV2+12(2C)(2V)2

           Ui=E+8E=9E

           Common potential difference across capacitors, finally

           ⇒V0=5V/3

           Final potential energy of system

           Uf=12CV02+12(2C)V02

           Uf=3C2V02=3C2(5V3)2=12CV2(253)=253E

           Loss of energy

           ⇒Ui-Uf=9E-25E3=(27-25)E3=2E3

 



Q 2 :

A parallel plate capacitor consisting of two circular plates of radius 10 cm is being charged by a constant current of 0.15 A. If the rate of change of potential difference between the plates is 7×108 V/s then the integer value of the distance between the parallel plates is (Take ε0=9×10–12Fm, π=227)______ μm          [2025]



(1320)

V=QC=it(ε0Ad)=itdε0(πr2)

⇒ d=ε0(πr2)i(Vt)

d=(9×10–12)(227)(0.1)20.15(7×108) m=1320 μm



Q 3 :

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Two metallic spheres are charged to the same potential. One of them is hollow and another is solid, and both have the same radii. Solid sphere will have lower charge than the hollow one.

Reason R: Capacitance of metallic spheres depend on the radii of spheres.

In the light of the above statements, choose the correct answer from the options given below.                [2023]

  • A is false but R is true

     

  • Both A and R are true and R is the correct explanation of A

     

  • A is true but R is false

     

  • Both A and R are true but R is not the correct explanation of A

     

(1)

Potential of a conducting sphere is

V=KQR  (Solid as well as hollow)

V1=V2 and R1=R2

∴  Q1=Q2



Q 4 :

A capacitor of capacitance C is charged to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is       [2023]

  • CV2ε0

     

  • 2CVε0

     

  • CVε0

     

  • zero

     

(3)

ϕ=qinε0=Qε0=CVε0



Q 5 :

As shown in the figure, two parallel plate capacitors having equal plate area of 200 cm2 are joined in such a way that a≠b. The equivalent capacitance of the combination is x ε0 F. The value of x is ___________ .               [2023]



(5)

C=ε0A(d-c)=ε0×200×10-44×10-3

∴  x=5

The situation is equivalent to a conducting slab placed between the plates.



Q 6 :

Statement – I: If the distance between plates of a charged isolated capacitor increases, then the potential energy in the electric field of capacitor increases.

Statement – II: The energy stored in a capacitor is always directly proportional to separation between the plates.

  • Both Statement – I and Statement – II are true

     

  • Statement – I is true and Statement – II is false

     

  • Statement – I is false and Statement – II is true

     

  • Both Statement – I and Statement – II are false

     

(2)

For a given charge U=a22C=Q2d2ε0A, i.e., U∝d.



Q 7 :

Two charged conducting spheres of radii a and b are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:

  • ab

     

  • ba

     

  • 1

     

  • ab

     

(1)

V=KQR



Q 8 :

A sphere of capacitance 100 pF is charged to a potential of 100 V. Another identical undercharged metal sphere is brought in contact with the charged sphere, then the change in the total energy stored on these spheres, when they touch is α×10-7 J. The value of α is ______. (combined capacitance of spheres is 200 pF).         [2026]

  • 5

     

  • 52

     

  • 72

     

  • 92

     

(2)

Q=CV=10-8 C

U1=Q22C=10-162×10-10 J=5×10-7 J

Now, when identical metal sphere is touched, charge on them becomes equal, Q2

Energy Uf=(Q2)22C×2=Q24C=52×10-7 J

ΔU=Uf-Ui=5×10-7-52×10-7=2.5×10-7 J