Q 1 :    

Three capacitors of capacitances 25 μF30 μF, and 45 μF are connected in parallel to a supply of 100 V. Energy stored in the above combination is E. When these capacitors are connected in series to the same supply, the stored energy is 9xE. The value of x is _______ .               [2024]



(86)     In series combination: C1=25+30+45=100μF

            In parallel combination: 1C2=125+130+145C2=45043μF

             Energy E=12CV2

             E2E1=C2C1=450/43100=986E2=986E

             986E=9xEx=86

 



Q 2 :    

A capacitor is made of a flat plate of area A and a second plate having a stair-like structure as shown in the figure. If the area of each stair is A3 and the height is d, the capacitance of the arrangement is:      [2024]

  • 11ϵ0A18d

     

  • 13ϵ0A17d

     

  • 11ϵ0A20d 

     

  • 18ϵ0A11d

     

(1)

All capacitors are in parallel combination.

Also, effective area is common area only

Ceq=C1+C2+C3

=ϵ0A3×d+ϵ0A3×2d+ϵ0A3×3d

=6ϵ0A+3ϵ0A+2ϵ0A18d=11ϵ0A18d

 



Q 3 :    

Two identical capacitors have same capacitance C. One of them is charged to the potential V and other to the potential 2V. The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is           [2024].

  • 14CV2

     

  • 2CV2

     

  • 12CV2

     

  • 34CV2

     

(1)

Initial energy =12CV2+12C×4V2=5CV22

2CV-qC=CV+qC

2CV-CV=2q

q=CV2

Final charge on capacitor =3CV2

Energyfinal=2×(3CV2)2×12C=9CV24

Decrease in Energy =5CV22-9CV24=CV24

 



Q 4 :    

16Ω wire is bent to form a square loop. A 9V battery with internal resistance 1Ω is connected across one of its sides. If a 4μF capacitor is connected across one of its diagonals, the energy stored by the capacitor will be x/2 μJ, where x = ______.       [2024]



(81)

At steady state, the current supplied from the battery,

I=VReq=91+12×412+4=94A

I1=94×416=916A

VA-VB=I1×8=916×8=92V

 U=12×4×814μJ=812μJ

 x=81



Q 5 :    

Two capacitors C1 and C2 are connected in parallel to a battery. Charge-time graph is shown below for the two capacitors. The energy stored with them are U1 and U2, respectively. Which of the given statements is true?          [2025]

  • C1>C2, U1>U2

     

  • C2>C1, U2>U1

     

  • C1>C2, U1<U2

     

  • C2>C1, U2<U1

     

(2)

For a capacitor at steady state

q = CV and U=12CV2

Since C1 and C2 are connected in parallel, V1=V2

Also from graph q1<q2

 C1V1<C2V2

i.e., C1<C2 or C2>C1

U1U2=C1V12C2V22=C1C2<1

or U1<U2 or U2>U1



Q 6 :    

A capacitor, C1=6 μF is charged to a potential difference of V0=5 V using a 5 V battery. The battery is removed and another capacitor, C2=12 μF is inserted in place of the battery. When the switch 'S' is closed, the charge flows between the capacitors for some time until equilibrium condition is reached. What are the charges (q1 and q2) on the capacitors C1 and C2 when equilibrium condition is reached?          [2025]

  • q1=15 μC, q2=30 μC

     

  • q1=30 μC, q2=15 μC

     

  • q1=10 μC, q2=20 μC

     

  • q1=20 μC, q2=10 μC

     

(3)

Initially Finally
q1'=6×5=30 μC

6VC+12VC=30+0

18VC=30

 VC=3018=53 Volt

 q1=6×53=10 μC

and q2=12×53=20 μC

 



Q 7 :    

Using a battery, a 100 pF capacitor is charged to 60 V and then the battery is removed. After that, a second uncharged capacitor is connected to the first capacitor in parallel. If the final voltage across the second capacitor is 20 V, its capacitance is (in pF)          [2025]

  • 600

     

  • 200

     

  • 400

     

  • 100

     

(2)

New potential =C0V0C0+C=V03

3C0V0=C0V0+CV0

2C0V0=CV0

C=2C0=2×100=200 pF



Q 8 :    

Four capacitors each of capacitance 16 μF are connected as shown in the figure. The capacitance between points A and B is : ______ (in μF).          [2025]



(64)

Ceq=4C=64



Q 9 :    

Space between the plates of a parallel plate capacitor of plate area 4 cm2 and separation of (d) 1.77 mm, is filled with uniform dielectric materials with dielectric constants (3 and 5) as shown in figure. Another capacitor of capacitance 7.5 pF is connected in parallel with it. The effective capacitance of this combination is ______ pF. (Given ε0=8.85×1012 F/m)        [2025]



(15)

1C=1C1+1C2=d/2Ak1ε0+d/2Ak2ε0

    =(1k1+1k2)d2Aε0=(13+15)d2Aε0

1C=415dAε0

C=154×Aε0d

     =154×4×104×8.85×10121.77×103=7.5 pF

Finally equivalent capacitance (Ceq) = 7.5 + 7.5 = 15 pF