Q 1 :    

An alternating current at any instant is given by i=[6+56sin(100πt+π3)]A. The rms value of the current is _______ A    [2024]



(8)     If i=a+b sin(ωt+θ)

         irms=a2+b22

        irms=36+562

        =36+28=64=8A

 



Q 2 :    

An alternating voltage V(t)=220 sin 100πt volt is applied to a purely resistive load of 50Ω. The time taken for the current to rise from half of the peak value to the peak value is                [2024]

  • 5 ms

     

  • 3.3 ms

     

  • 7.2 ms

     

  • 2.2 ms

     

(2)

V(t)=220sin(100πt)

I=VsR=22050sin(100πt)

I=225sin(100πt)

cosθ=I02I0=12θ=60°=π3

Using phasor, t=π/3100π

t=1300 sec=103 msec

t=3.3 msec