An electric bulb rated as 100 W – 220 V is connected to an ac source of rms voltage 220 V. The peak value of current through the bulb is: [2025]

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Solution

Q.
An electric bulb rated as 100 W – 220 V is connected to an ac source of rms voltage 220 V. The peak value of current through the bulb is: [2025]

1 0.64 A

2 0.45 A

3 2.2 A

4 0.32 A

Ans.
(1)

$R_{B} = \frac{V^{2}}{P} = \frac{220 \times 220}{100} = 484 Ω$

$I_{rms} = \frac{V_{rms}}{R} = \frac{220}{484} = \frac{10}{22} = \frac{5}{11} A$

$I_{0} = \frac{5 \sqrt{2}}{11} = 0.64 A$

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