What is the lateral shift of a ray refracted through a parallel sided glass slab of thickness 'h' in terms of the angle of incidence 'i' amd angle of refraction 'r', if the glass slab is placed in air medium? [2025]

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Solution

Q.
What is the lateral shift of a ray refracted through a parallel sided glass slab of thickness 'h' in terms of the angle of incidence 'i' and angle of refraction 'r', if the glass slab is placed in air medium [2025]

Solution

Q.
What is the lateral shift of a ray refracted through a parallel sided glass slab of thickness 'h' in terms of the angle of incidence 'i' and angle of refraction 'r', if the glass slab is placed in air medium [2025]

1 $\frac{h \tan (i - r)}{\tan r}$

2 $\frac{h \cos (i - r)}{\sin r}$

3 h

4 $\frac{h \sin (i - r)}{\cos r}$

Ans.
(4)

AB = h sec r

BC = h sec r sin (i – r)

BC = $\frac{h \sin (i - r)}{\cos r}$

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Solution

Q. What is the lateral shift of a ray refracted through a parallel sided glass slab of thickness 'h' in terms of the angle of incidence 'i' and angle of refraction 'r', if the glass slab is placed in air medium [2025]

1 h tan (i–r)tan r

2 h cos (i–r)sin r

3 h

4 h sin (i–r)cos r

Ans. (4) AB = h sec r BC = h sec r sin (i – r) BC = h sin (i–r)cos r

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Q.
What is the lateral shift of a ray refracted through a parallel sided glass slab of thickness 'h' in terms of the angle of incidence 'i' and angle of refraction 'r', if the glass slab is placed in air medium [2025]

1 $\frac{h \tan (i - r)}{\tan r}$

2 $\frac{h \cos (i - r)}{\sin r}$

4 $\frac{h \sin (i - r)}{\cos r}$

Ans.
(4)

AB = h sec r

BC = h sec r sin (i – r)

BC = $\frac{h \sin (i - r)}{\cos r}$