Q.

A container contains a liquid with refractive index of 1.2 up to a height of 60 cm and another liquid having refractive index 1.6 is added to height H above first liquid. If viewed from above, the apparent shift in the position of bottom of container is 40 cm. The value of H is __________ cm. (Consider liquids are immisible)          [2025]


Ans.

(80)

Shift t=40 cm

t=60(111.2)+H(111.6)

 40=(16)60+H(38)

30=H×38  H=80 cm