A container contains a liquid with refractive index of 1.2 up to a height of 60 cm and another liquid having refractive index 1.6 is added to height H above first liquid. If viewed from above, the apparent shift in the position of bottom of container is 4

Question

A container contains a liquid with refractive index of 1.2 up to a height of 60 cm and another liquid having refractive index 1.6 is added to height H above first liquid. If viewed from above, the apparent shift in the position of bottom of container is 40 cm. The value of H is __________ cm. (Consider liquids are immisible) [2025]

Smart Achievers · Accepted Answer

(80)

Shift $△ t = 40 cm$

$△ t = 60 (1 - \frac{1}{1.2}) + H (1 - \frac{1}{1.6})$

$\Rightarrow 40 = (\frac{1}{6}) 60 + H (\frac{3}{8})$

$\Rightarrow 30 = H \times \frac{3}{8} \Rightarrow H = 80 cm$

Solution

Ans.
(80)

Shift $△ t = 40 cm$

$△ t = 60 (1 - \frac{1}{1.2}) + H (1 - \frac{1}{1.6})$

$\Rightarrow 40 = (\frac{1}{6}) 60 + H (\frac{3}{8})$

$\Rightarrow 30 = H \times \frac{3}{8} \Rightarrow H = 80 cm$

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Solution

Ans. (80) Shift △t=40 cm △t=60(1–11.2)+H(1–11.6) ⇒ 40=(16)60+H(38) ⇒30=H×38 ⇒ H=80 cm

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Ans.
(80)

Shift $△ t = 40 cm$

$△ t = 60 (1 - \frac{1}{1.2}) + H (1 - \frac{1}{1.6})$

$\Rightarrow 40 = (\frac{1}{6}) 60 + H (\frac{3}{8})$

$\Rightarrow 30 = H \times \frac{3}{8} \Rightarrow H = 80 cm$