Q.

The term independent of x in the expansion of (2x5-12xx)11 is

1 5th term  
2 6th term  
3 11th term  
4 no term  

Ans.

(4)

Let Tr+1 be general term of given expansion

∴  Tr+1=Cr11(2x5)11-r(-12xx)r

=Cr11(25)11-r×(-12)rx11-r2-3r2

∴  Tr+1=Cr11(25)11-r(-12)rx(11-4r)/2

For a term independent of x, put 11-4r2=0  or  r=114

But r can not be in fraction.

∴  There is no term independent of x.