The term independent of x in the expansion of (2x5-12xx)11 is
(4)
Let Tr+1 be general term of given expansion
∴ Tr+1=Cr11(2x5)11-r(-12xx)r
=Cr11(25)11-r×(-12)rx11-r2-3r2
∴ Tr+1=Cr11(25)11-r(-12)rx(11-4r)/2
For a term independent of x, put 11-4r2=0 or r=114
But r can not be in fraction.
∴ There is no term independent of x.