The ninth term of the expansion ( 3 x - 1 2 x ) 8 is

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Solution

Q.
The ninth term of the expansion ${(3 x - \frac{1}{2 x})}^{8}$ is

1 $\frac{1}{512 x^{9}}$

2 $\frac{- 1}{512 x^{9}}$

3 $\frac{- 1}{256 x^{8}}$

4 $\frac{1}{256 x^{8}}$

Ans.
(4)

$Given expansion is {(3 x - \frac{1}{2 x})}^{8}$

$T_{9} = {}^{8}C_{8} {(3 x)}^{0} {(\frac{- 1}{2 x})}^{8} = \frac{1}{256 x^{8}}$

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