Q.

The term independent of x in the expansion of [x3+32x2]10 is:

1 54  
2 74  
3 94  
4 45  

Ans.

(1)

Let (r+1)th term in the expansion of

[x3+32x2]10 is independent of x

So  Tr+1=Cr10(x3)10-r(32x2)r

=Cr10(13)10-r(32)rx10-5r2

Putting x(10-5r2) equal to x0  ⇒  10-5r2=0  ⇒  r=2

∴  T2+1=C210(13)10-2(32)2=54