The general solution of the differential equation dydx=cotx coty is:
(2)
Ans. sin x=C sec y
Explanation:
dydx=cotx coty
⇒ cotx dx-tany dy=0
Integrating on both sides, we get
⇒ ∫cotx dx-∫tany dy=0
log sinx-log secy=logC
⇒ log(sinxsecy)=logC
⇒ sin x=C sec y