The integrating factor of differential equation d y d x + y tan x - sec x = 0 is:

Question

The integrating factor of differential equation $\frac{d y}{d x} + y \tan x - \sec x = 0$ is:

Smart Achievers · Accepted Answer

(2)

Ans. $\sec x$

Explanation:

Given that,

$\frac{d y}{d x} + y \tan x - \sec x = 0$

Here, $P = \tan x,$ $Q = \sec x$

$IF = e^{\int P d x} = e^{\int \tan x d x}$

$= e^{(\log \sec x)}$

$= \sec x$

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