The solution of xdydx+y=ex is:
(1)
Ans. y=exx+kx
Explanation:
Given that,
xdydx+y=ex
⇒ dydx+yx=exx
which is a linear differential equation.
∴ IF=e∫1x dx=elogx=x
The general solution is
⇒ y·x=∫(exx·x)dx
⇒ y·x=∫ex dx
⇒ y·x=ex+k
⇒ y=exx+kx