The function f(x)=tanx is discontinuous on the set:
(3)
Ans. {x=(2n+1)π2:n∈Z}
Explanation:
When tan((2n+1)π2)=tan(nπ+π2)=-cotnπ.
It is not defined at the integral points (n∈Z).
Hence, f(x)=tanx is discontinuous at (2n+1)π2