Q.

The function f(x)=tanx is discontinuous on the set:

1 {x=nπ:n∈Z}  
2 {x=2nπ:n∈Z}  
3 {x=(2n+1)π2:n∈Z}  
4 {x=nπ2:n∈Z}  

Ans.

(3)

Ans.     {x=(2n+1)π2:n∈Z}

Explanation:

When  tan((2n+1)π2)=tan(nπ+π2)=-cotnπ.

It is not defined at the integral points (n∈Z).

Hence, f(x)=tanx is discontinuous at (2n+1)π2