The equation of smallest degree with real coefficients having 2+3i as one of the roots is
(3)
Since complex roots always exist in pairs
So other root will be 2-3i
S=sum of roots=2+3i+2-3i=4
P=Product of roots=(2+3i)(2-3i)=4+9=13
So, required equation will be
x2-Sx+P=0⇒x2-4x+13=0