If α,β are the roots of the equation ax2+bx+c=0, then the value of 1aα+b+1aβ+b equals to
(2)
Since, α,β are roots of equation
ax2+bx+c=0
∴ α+β=-ba,αβ=ca} ...(i)
Taking, 1aα+b+1aβ+b=a(α+β)+2b(aα+b)(aβ+b)
=a(α+β)+2ba2αβ+ab(α+β)+b2
=a(-ba)+2ba2·ca+ab(-ba)+b2=bac (Using (i))