If α+β=4 and α3+β3=44, then α,β are the roots of the equation
(1)
α+β=4, α3+β3=44
Taking, (α+β)3=α3+β3+3αβ(α+β)
(4)3=44+3αβ(4)⇒64-44=12αβ
⇒12αβ=20⇒αβ=2012=53
So, equation will be x2-4x+p=0
x2-4x+53=0 or 3x2-12x+5=0