Q.

If α+β=4 and α3+β3=44, then α,β are the roots of the equation

1 3x2-12x+5=0  
2 3x2+9x+11=0  
3 9x2-27x+20=0  
4 4x2+22x+15=0  

Ans.

(1)

α+β=4,  α3+β3=44

Taking, (α+β)3=α3+β3+3αβ(α+β)

(4)3=44+3αβ(4)⇒64-44=12αβ

⇒12αβ=20⇒αβ=2012=53

So, equation will be x2-4x+p=0

   x2-4x+53=0    or    3x2-12x+5=0