The difference between threshold wavelengths for two metal surfaces A and B having work function and in nm is: (Given, ) [2023]

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Solution

Q.
The difference between threshold wavelengths for two metal surfaces A and B having work function $ϕ_{A} = 9 eV$ and $ϕ_{B} = 4.5 eV$ in nm is: (Given, $h c = 1242 eV nm$ ) [2023]

1 264

2 138

3 276

4 540

Ans.
(2)

$λ_{A} = (\frac{1242}{9}) = 138 nm$

$λ_{B} = (\frac{1242}{4.5}) = 276 nm$

$λ_{B} - λ_{A} = 138 nm$

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