When a light of a given wavelength falls on a metallic surface the stopping potential for photoelectrons is 3.2 V. If a second light having wavelength twice of first light is used, the stopping potential drops to 0.7 V. The wavelength of first light is __

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Solution

Q.
When a light of a given wavelength falls on a metallic surface the stopping potential for photoelectrons is 3.2 V. If a second light having wavelength twice of first light is used, the stopping potential drops to 0.7 V. The wavelength of first light is _______ m.

$(h = 6.63 \times 10^{- 34} J s, e = 1.6 \times 10^{- 19} C, c = 3 \times 10^{8} m/s)$ [2026]

1 $2.2 \times 10^{- 8}$

2 $3.1 \times 10^{- 7}$

3 $2.9 \times 10^{- 8}$

4 $2.5 \times 10^{- 7}$

Ans.
(4)

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