Light is incident on a metallic plate having work function If the produced photoelectrons have zero kinetic energy then the angular frequency of the incident

Question

Light is incident on a metallic plate having work function $110 \times 10^{- 20} J .$ If the produced photoelectrons have zero kinetic energy then the angular frequency of the incident light is ______ rad/s.
$(h = 6.63 \times 10^{- 34} J·s)$ [2026]

Smart Achievers · Accepted Answer

(2)

$ϕ = h ν$

$ν = \frac{ϕ}{h}$

$ω = 2 π ν = \frac{2 π ϕ}{h} = \frac{2 \times 3.14 \times 110 \times 10^{- 2}}{6.63 \times 10^{- 34}}$

$ω = 1.04 \times 10^{16} rad/sec$

Solution

Q.
Light is incident on a metallic plate having work function $110 \times 10^{- 20} J .$ If the produced photoelectrons have zero kinetic energy then the angular frequency of the incident light is ______ rad/s.
$(h = 6.63 \times 10^{- 34} J·s)$ [2026]

1 $1.66 \times 10^{15}$

2 $1.04 \times 10^{16}$

3 $1.04 \times 10^{13}$

4 $1.66 \times 10^{16}$

Ans.
(2)

$ϕ = h ν$

$ν = \frac{ϕ}{h}$

$ω = 2 π ν = \frac{2 π ϕ}{h} = \frac{2 \times 3.14 \times 110 \times 10^{- 2}}{6.63 \times 10^{- 34}}$

$ω = 1.04 \times 10^{16} rad/sec$

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Solution

Q. Light is incident on a metallic plate having work function 110×10-20J. If the produced photoelectrons have zero kinetic energy then the angular frequency of the incident light is ______ rad/s. (h=6.63×10-34 J·s) [2026]

1 1.66×1015

2 1.04×1016

3 1.04×1013

4 1.66×1016

Ans. (2) ϕ=hν ν=ϕh ω=2πν=2πϕh=2×3.14×110×10-26.63×10-34 ω=1.04×1016 rad/sec