The current i in the network is

Question

The current $i$ in the network is _______ $\times 10^{- 1} A$

Smart Achievers · Accepted Answer

(3)

Both the diodes are reverse biased, so, there is no flow of current through $\times 10^{- 1} A$ and $20 Ω$ resistances. Now, two resistors of $10 Ω$ and two resistors of $5 Ω$ are in series.

Hence, current $I$ through the network = 0.3A.

Solution

Q.
The current $i$ in the network is _______ $\times 10^{- 1} A$

Ans.
(3)

Both the diodes are reverse biased, so, there is no flow of current through $5 Ω$ and $20 Ω$ resistances. Now, two resistors of $10 Ω$ and two resistors of $5 Ω$ are in series.

Hence, current $I$ through the network = 0.3A.

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Solution

Q. The current i in the network is _______ ×10-1A

Ans. (3) Both the diodes are reverse biased, so, there is no flow of current through 5Ω and 20Ω resistances. Now, two resistors of 10Ω and two resistors of 5Ω are in series. Hence, current I through the network = 0.3A.

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Q.
The current $i$ in the network is _______ $\times 10^{- 1} A$

Ans.
(3)

Both the diodes are reverse biased, so, there is no flow of current through $5 Ω$ and $20 Ω$ resistances. Now, two resistors of $10 Ω$ and two resistors of $5 Ω$ are in series.

Hence, current $I$ through the network = 0.3A.