Q.

The electric current through a wire varies with time as I=I0+βt where I0=20A and β=3A/s. The amount of electric charge crossed through a section of the wire in 20 sec is                           [2024]

1 80 C  
2 1000 C  
3 800 C  
4 1600 C  

Ans.

(2)       

           Given that, current I=I0+βt

            Also, I0=20A and β=3A/s

            Hence, dq/dt=20+3tdq=(20+3t)dt

            0qdq=020(20+3t)dt

            q=[20t+3t22]020=1000C