Q.

The current in a conductor is expressed as I=3t2+4t3, where I is in Ampere and t is in second. The amount of electric charge that flows through a section of the conductor during t=1s to t=2s is _________ C.               [2024]


Ans.

(22)       I=3t2+4t3

              dQ=Idt

              Q=12(3t2+4t3)dt

                   =[t3+t4]12

                    =(8+16)-(2)=22C