Q.

Let A={x:x2−5x+6=0}, B = {2, 4}, C = {4, 5} then A×(B∩C)

1 {(2, 4), (3, 4)}  
2 {(4, 2), (4, 3)}  
3 {(2, 4), (3, 4), (4, 4)}  
4 {(2, 2), (3, 3), (4, 4), (5, 5)}  

Ans.

(1)

A={x:x2-5x+6=0}

x2-5x+6=0

⇒(x-3)(x-2)=0⇒x=3, 2

A={3,2},  B={2,4},  C={4,5},  B∩C={4}

A×(B∩C)={3,2}×{4}={(3,4),(2,4)}