The cartesian product A×A has 9 elements among which two elements are found (−1, 0) and (0, 1), then set A =
(2)
∵ A×A has 9 elements
∴ Set A has exactly 3 elements.
Also (-1,0),(0,1)∈A×A⇒-1,0,1∈A
∴ A={-1,0,1}