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Solution


Q.

In Young’s double slits experiment, the position of 5th bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1 m and wavelength of used monochromatic light is 600 nm. The separation between the slits is                     [2023]
1 12 μm  
2 60 μm  
3 36 μm  
4 48 μm  

Ans.

(2)

Position of 5th bright,  5Dλd=5×10-2 m

λ=600×10-9 m=6×10-7 m

D=1 m,  d=?

d=60 μm