Two light waves of wavelengths 800 and 600 nm are used in Young’s double slit experiment to obtain interference fringes on a screen placed 7 m away from plane of slits. [2023]

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Solution

Q.
Two light waves of wavelengths 800 and 600 nm are used in Young’s double slit experiment to obtain interference fringes on a screen placed 7 m away from plane of slits. If the two slits are separated by 0.35 mm, then shortest distance from the central bright maximum to the point where the bright fringes of the two wavelength coincide will be ________ mm. [2023]

Ans.
(48)

$ω_{1} = \frac{λ_{1} D}{d} and ω_{2} = \frac{λ_{2} D}{d}$

$ω_{1} = 16 mm and ω_{2} = 12 mm$

$so LCM (ω_{1}, ω_{2}) = 48 mm$

$so at 48 mm distance both bright fringes will be found.$

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