The width of fringe is 2 mm on the screen in a double slits experiment for the light of wavelength of 400 nm. The width of the fringe for the light of wavelength 600 nm will be ________ [2023]

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Solution

Q.
The width of fringe is 2 mm on the screen in a double slits experiment for the light of wavelength of 400 nm. The width of the fringe for the light of wavelength 600 nm will be ________ [2023]

1 4 mm

2 1.33 mm

3 2 mm

4 3 mm

Ans.
(4)

$Fringe width (β) = \frac{D λ}{d}$

$\Rightarrow \frac{β_{2}}{β_{1}} = \frac{λ_{2}}{λ_{1}}$

$\Rightarrow \frac{β_{2}}{2 mm} = \frac{600 nm}{400 nm} = \frac{3}{2}$

$\Rightarrow β_{2} = 3 mm$

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