In the adjoining circuit, initially the switch S is open. The switch ‘S’ is closed at t = 0. The difference between the maximum and minimum current that can flow through the battery is

Question

Smart Achievers · Accepted Answer

(3)

$i_{\max} (After long time) = \frac{10 V}{5 Ω} = 2 A$

$i_{\min} (at t = 0) = \frac{10}{10} = 1 A$

Solution

Q.
In the adjoining circuit, initially the switch S is open. The switch ‘S’ is closed at t = 0. The difference between the maximum and minimum current that can flow through the battery is

1 2 A

2 3 A

3 1 A

4 0.5 A

Ans.
(3)

$i_{\max} (After long time) = \frac{10 V}{5 Ω} = 2 A$

$i_{\min} (at t = 0) = \frac{10}{10} = 1 A$

Want Us to Email you About Special Offers & Updates?