An inductor of inductance 10 mH having resistance of 100 is connected to battery of E.M.F. 1.0 V through a switch as shown in the figure below.

Question

An inductor of inductance 10 mH having resistance of 100 $Ω$ is connected to battery of E.M.F. 1.0 V through a switch as shown in the figure below. After switch is closed, the ratio of instantaneous voltages across the inductor when the current passing through it is 2 mA and 4 mA is ______. [2026]

Smart Achievers · Accepted Answer

(1)

$Apply KVL: E - i R - V_{L} = 0$

$V_{L} = E - i R = 1 - 100 i$

$At i_{1} = 2 \times 10^{- 3} A, V_{L_{1}} = 0.8 V$

$At i_{2} = 4 \times 10^{- 3} A, V_{L_{2}} = 0.6 V$

$\Rightarrow \frac{V_{L_{1}}}{V_{L_{2}}} = \frac{4}{3}$

Solution

1 $\frac{4}{3}$

2 $\frac{3}{4}$

3 $\frac{5}{3}$

4 $\frac{3}{5}$

Ans.
(1)

$Apply KVL: E - i R - V_{L} = 0$

$V_{L} = E - i R = 1 - 100 i$

$At i_{1} = 2 \times 10^{- 3} A, V_{L_{1}} = 0.8 V$

$At i_{2} = 4 \times 10^{- 3} A, V_{L_{2}} = 0.6 V$

$\Rightarrow \frac{V_{L_{1}}}{V_{L_{2}}} = \frac{4}{3}$

Want Us to Email you About Special Offers & Updates?

Solution

1 43

2 34

3 53

4 35