If the binding energy of ground state electron in a hydrogen atom is , then, the energy required to remove the electron from the second excited state of will be: . The value of is _______ . [2023]

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Solution

Q.
If the binding energy of ground state electron in a hydrogen atom is $13.6 eV$ , then, the energy required to remove the electron from the second excited state of ${Li}^{2 +}$ will be: $x \times 10^{- 1} eV$ . The value of $x$ is _______ . [2023]

Ans.
(136)

$E_{H} = 13.6$

$E_{Li}^{2} = 13.6 \frac{Z^{2}}{n^{2}} = 13.6 \times \frac{9}{9} = 13.6 eV = 136 \times 10^{- 1} eV$

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