The binding energy for the following nuclear reactions are expressed in MeV. If denote the stability of and respectively, then the correct order is: [2026]

Question

The binding energy for the following nuclear reactions are expressed in MeV.

${}_{2}{He}^{3} + {{}_{0}n}^{1} \to {}_{2}{He}^{4} + 20 MeV$

${}_{2}{He}^{4} + {{}_{0}n}^{1} \to {}_{2}{He}^{5} - 0.9 MeV$

If $X_{3}, X_{4}, X_{5}$ denote the stability of ${}_{2}{He}^{3}, {}_{2}{He}^{4}$ and ${}_{2}{He}^{5}$ respectively, then the correct order is: [2026]

Smart Achievers · Accepted Answer

(1)

${BE}_{{He}^{4}} - {BE}_{{He}^{3}} = 20 MeV \dots (1)$

${BE}_{{He}^{5}} - {BE}_{{He}^{4}} = - 0.9 MeV \dots (2)$

$From eq (1) & (2)$

${BE}_{{He}^{4}} > {BE}_{{He}^{5}} > {BE}_{{He}^{3}}$

$X_{4} > X_{5} > X_{3}$

Solution

1 $X_{4} > X_{5} > X_{3}$

2 $X_{4} < X_{5} < X_{3}$

3 $X_{4} > X_{5} < X_{3}$

4 $X_{4} = X_{5} = X_{3}$

Ans.
(1)

${BE}_{{He}^{4}} - {BE}_{{He}^{3}} = 20 MeV \dots (1)$

${BE}_{{He}^{5}} - {BE}_{{He}^{4}} = - 0.9 MeV \dots (2)$

$From eq (1) & (2)$

${BE}_{{He}^{4}} > {BE}_{{He}^{5}} > {BE}_{{He}^{3}}$

$X_{4} > X_{5} > X_{3}$

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Solution

Q. The binding energy for the following nuclear reactions are expressed in MeV. He23+n01→He24+20 MeV He24+n01→He25-0.9 MeV If X3,X4,X5 denote the stability of He23,He24 and He25 respectively, then the correct order is: [2026]

1 X4>X5>X3

2 X4<X5<X3

3 X4>X5<X3

4 X4=X5=X3