A common example of alpha decay is Given: The energy released during the alpha decay of is ________ MeV. [2023]

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Solution

Q.
A common example of alpha decay is

   ${}_{92}^{238}U \to {}_{90}^{234}{Th} + {}_{2}{He}^{4} + Q$

Given:   ${}_{92}^{238}U = 238.05060 u$

   ${}_{90}^{234}{Th} = 234.04360 u$

   ${}_{2}^{4}{He} = 4.00260 u and 1 u = 931.5 \frac{MeV}{e^{2}}$

The energy released $(Q)$ during the alpha decay of ${}_{92}^{238}U$ is ________ MeV. [2023]

Ans.
(4)

$Energy released = {(Δ m)}_{amu} \times 931.5 MeV$

$= {(m_{u} - m_{Th} - m_{He})}_{amu} \times 931.5 MeV$

$= 0.0044 \times 931.5 MeV = 4.0986 MeV$

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