If Na={an:n∈N}, then N5∩N7 = (Here N is the set of natural numbers)
(3)
Na={an:n∈N}
N5={5,10,15,20,25,…}
N7={7,14,21,28,35,…}
N5∩N7={35,70,105,…}=N35
∴ N5∩N7=N35