Given A = {x | x is a root of x² ? 1 = 0}, B = {x | x is a root of x² ? 2x + 1 = 0}. Then

Question

Given $A = {x ∣ x is a root of x^{2} - 1 = 0}$ , $B = {x ∣ x is a root of x^{2} - 2 x + 1 = 0}$ . Then

Smart Achievers · Accepted Answer

(3)

$We have A = {x ∣ x is a root of x^{2} - 1 = 0}$ $= {x ∣ x is a root of (x - 1) (x + 1) = 0} \Rightarrow A = {1, - 1}$

$B = {x ∣ x is a root of x^{2} - 2 x + 1 = 0}$ $= {x ∣ x is a root of {(x - 1)}^{2} = 0}$

$\Rightarrow B = {1}$

$\Rightarrow A \cup B = {1, - 1} = A$

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