Q.

If k is the coefficient of x4 in the expansion of (1+2x+3x2)6, then the sum of the digits of k is _______.


Ans.

(6)

The general term is 6!α!β!γ!1α(2x)β·(3x2)γ

β-2γ=4,  α+β+γ=6⇒α=2-3γ

β=2γ+4  ∴  (α,β,γ)=(2,4,0)

The desired coefficient is

6!2! 4!·24=15×16=240