Q.

If the magnitude of the coefficient of x7 in the expansion of (ax2+1bx)8, where a,b are positive numbers, is equal to the magnitude of the coefficient of x-7 in the expansion of (ax+1bx2)8, then |ab| is equal to _________.


Ans.

(1)

In the expansion (ax2+1bx)8, (r+1)th term is

Tr+1=Cr8(ax2)8-r(1bx)r

Let the (r+1)th term contain x7.

∴  x16-3r=x7⇒r=3

∴  Coefficient of x7=C38 a5b-3                      ...(i)

In the expansion (ax+1bx2)8, (r+1)th term is

Tr+1=Cr8(ax)8-r(1bx2)r=Cr8 a8-r(b)-rx8-3r

Let the (r+1)th term contain x-7.

∴  x8-3r=x-7⇒r=5

∴  Coefficient of x-7=C58 a3b-5                  ...(ii)

From (i) and (ii), we have  |C38a5b-3|=|C58a3b-5|

⇒  a2b2=1⇒ab=1