Q.

If the term independent of x in the expansion of (x-λx2)10  is 405, then the value of |4λ| is _________.


Ans.

(12)

Let (r+1)th term is independent of x.

We have, Tr+1=Cr10(x)10-r·(-λx2)r

                               =Cr10·x 5-r2-2r·(-λ)r

The term will be independent of x if 5-r2-2r=0

⇒  r=2

Then,  T2+1=C210·(-λ)2=45λ2=405    (Given)

∴  λ2=9⇒λ=±3⇒|4λ|=12