If the term independent of x in the expansion of (x-λx2)10 is 405, then the value of |4λ| is _________.
(12)
Let (r+1)th term is independent of x.
We have, Tr+1=Cr10(x)10-r·(-λx2)r
=Cr10·x 5-r2-2r·(-λ)r
The term will be independent of x if 5-r2-2r=0
⇒ r=2
Then, T2+1=C210·(-λ)2=45λ2=405 (Given)
∴ λ2=9⇒λ=±3⇒|4λ|=12