If f'(x)=1x+x and f(1)=52, then f(x)=
(1)
Ans. logx+x22+2
Explanation
f(x)=∫f'(x) dx=∫(1x+x)dx
=logx+x22+C
f(1)=log1+122+C
⇒ 52=0+12+C
⇒ C=2
∴ f(x)=logx+x22+2