By the inspection method, evaluate:
∫(au2+bu+c)du
(1)
Ans. a(u33)+b(u22)+cu+C
Explanation:
The given integral is ∫(au2+bu+c) du
∫(au2+bu+c) du=∫au2 du+∫bu du+∫c du
=a∫u2 du+b∫u du+c∫du
=a(u33)+b(u22)+cu+C