d x cos 2 x + sin 2 x =

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Solution

Q.
$\int \frac{d x}{\cos 2 x + \sin^{2} x} =$

1 $\sin x + C$

2 $\cos x + C$

3 $\tan x + C$

4 $0$

Ans.
(3)

Ans. $\tan x + C$

Explanation:

$\int \frac{d x}{\cos 2 x + \sin^{2} x} = \int \frac{d x}{\cos^{2} x - \sin^{2} x + \sin^{2} x}$

$= \int \frac{d x}{\cos^{2} x} = \int \sec^{2} x d x$

$= \tan x + C$

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