Q.

If A and B are not disjoint sets, then n(A∪B) is equal to

1 n(A)+n(B)  
2 n(A)+n(B)−n(A∩B)  
3 n(A)+n(B)+n(A∩B)  
4 n(A) n(B)  

Ans.

(2)

Since A,B are not disjoint sets,

⇒  A∩B≠ϕ

So, n(A∩B)≠0

So, n(A∪B)=n(A)+n(B)-n(A∩B)