If the roots of the quadratic equation x2+px+q=0 are tan30° and tan15°, respectively, then the value of 2+q-p is
(2)
α=tan30°, β=tan15° are roots of the equation x2+px+q=0.
∴ α+β=-p and αβ=q
Using tanA+tanB=tan(A+B)(1-tanA tanB)
⇒-p=1-q⇒q-p=1
⇒2+q-p=3