If 25th term of an A.P. is 15 and if its 15th term is 25, then the 40th term of the A.P. is ______.
(0)
Let a be the first term and d be the common difference.
According to question, T25=15⇒a+24d=15 ...(i)
T15=25⇒a+14d=25 ...(ii)
On solving (i) and (ii), we get a=39, d=-1
So, T40=a+39d=39+39(-1)=0