Q.

If 25th term of an A.P. is 15 and if its 15th term is 25, then the 40th term of the A.P. is ______.


Ans.

(0)

Let a be the first term and d be the common difference.

According to question,  T25=15⇒a+24d=15                ...(i)

T15=25⇒a+14d=25                                                      ...(ii)

On solving (i) and (ii), we get a=39, d=-1

So, T40=a+39d=39+39(-1)=0