Q.

For x≥0, the least value of a, for which 51+x+51-x, a2, 25x+25-x are three consecutive terms of an A.P., is equal to:

1 8  
2 12  
3 10  
4 16  

Ans.

(2)

Let 5x=t; t>0

A.M.≥G.M.

y2+5y-(2+a)=0; where y=t+1t≥2

Since a≥12