Let {an} and {bn} be two different sequences such that an+1=2+an ∀n∈N, a10=21 and bn=1anan+2 ∀n∈N, then the value of 15∑r=1∞br is
(2)
a1,a2,a3,… are in A.P.
d=2, a10=21⇒a1=3, an=2n+1
∑r=1∞br=∑n=1∞1(2n+1)(2n+5)
=14∑n=1∞(12n+1-12n+5)
=14[13+15]
=215